CODEWITHSUNDEEP
javascript
Sara Ree
Sara Ree

Reputation: 3543

implement a simple replace method and still get the capital words

I faced a simple but wired issue when I tried to replace a simple string:

const reference = 'then Max have gone with Sara.'; 
const selector = 'sara'; 
const phrase = 'Joe';
    
const result = reference.toLowerCase().replace(selector, phrase);
console.log(result);

I have a reference string and I want to replace a selector with a phrase.

The issue is the selector may be all lowercase so I need to conver reference to all lowercase words to be able to implement the replace method on two all lowercase strings right?

Now the issue shows up... when I convert the reference to lowercase words then all capital words (like Max as a name!) turn to lower case unexpectedly...

How can I do the replace method and still get this result:

then Max have gone with Joe.

Upvotes: 0

Views: 29

Answers (1)

Nina Scholz
Nina Scholz

Reputation: 386654

You could build a regular expression (RegExp) with some flags, like g for global (replace all ocurrences) and i for case insensitive search.

This approach does not cover special characters, but all letters and digits.

const
    reference = 'then Max have gone with Sara.',
    selector = 'sara',
    phrase = 'Joe',
    result = reference.replace(new RegExp(selector, 'gi'), phrase);
    
console.log(result);
console.log('foo.'.replace(new RegExp('.', 'gi'), '!')); // all chars are replaced

Upvotes: 2

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