CODEWITHSUNDEEP
python
adaba
adaba

Reputation: 384

Print Array of arrays to string using join and map

Assuming I have

a = [[0, 1], [0, 2]]

I want to, using a oneliner with join and map, print it as :

0 1
0 2

The closest I got is :

print("\n".join(map("".join, map(str, a))))

which gives :

[0, 1]
[0, 2]

Upvotes: 0

Views: 936

Answers (3)

AChampion
AChampion

Reputation: 30268

You are one level of iteration away:

In []:
print('\n'.join(' '.join(map(str, b)) for b in a))

Out[]:
0 1
0 2

Or:

In []:
print('\n'.join(map(' '.join, map(lambda b: map(str, b), a))))

Out[]:
0 1
0 2

Or if you really don't want to use lambda, then you can use functools.partial but now it is getting really ugly:

import functools as ft

In []:
print('\n'.join(map(' '.join, map(ft.partial(map, str), a))))

Out[]:
0 1
0 2

Upvotes: 1

wjandrea
wjandrea

Reputation: 33087

You can do this much more cleanly by using a for-loop with print instead of a one-liner with map and join:

for x in a:
    print(*x)

print automatically converts its arguments to string, joins them on spaces, and adds a trailing newline.

Upvotes: 0

Selcuk
Selcuk

Reputation: 59305

You can do it using map and lambda:

print("\n".join(map(lambda x: " ".join(map(str, x)), a)))
0 1
0 2

Edit: Just saw the comment with the same method, oh well.

Upvotes: 0

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