CODEWITHSUNDEEP
djangographqldjango-filter
muhammad hassan
muhammad hassan

Reputation: 63

graphene-django: 'Meta.model' without either 'Meta.fields' or 'Meta.exclude' has been deprecated since 0.15.0 and is now disallowed

I'm trying to return filtered results using django-graphene but it gives an error about error-message

class PatientType(DjangoObjectType):
    class Meta:
        model = Patients
        exclude = ('active',)
        interfaces = (relay.Node,)


class PatientsQuery(ObjectType):
    get_patient = graphene.Field(PatientType, id=graphene.Int())
    all_patients = graphene.List(
        PatientType, first=graphene.Int(), skip=graphene.Int(), phone_no=graphene.Int()
    )
    upcoming_appointments = DjangoFilterConnectionField(PatientType)


@permissions_checker([IsAuthenticated, CheckIsOrganizationActive])
def resolve_upcoming_appointments(self, info, **kwargs) -> List:
    d = datetime.today() - timedelta(hours=1)
    settings.TIME_ZONE  # 'Asia/Karachi'
    aware_datetime = make_aware(d)
    res = Patients.objects.filter(appointments__booking_date__gte=aware_datetime,
                                  appointments__booking_date__day=aware_datetime.day,
                                  appointments__status=True)
    if res:
        return res
    return []


class Query(
    organization_schema.OrganizationQuery,
    inventory_schema.MedicineQuery,
    patient_schema.PatientsQuery,
    graphene.ObjectType,
):
    pass

Upvotes: 6

Views: 3273

Answers (1)

JPG
JPG

Reputation: 88519

Specify the filter_fields attribute in the PatientType.Meta as

class PatientType(DjangoObjectType):
    class Meta:
        model = Patients
        exclude = ('active',)
        interfaces = (relay.Node,)
        filter_fields = ["field_1", "field_2"]

Alternatively, you can either set the filter_fields=[] or filterset_class attribute in the Meta section

More examples can be found in the doc, GraphenePython- Filtering

Upvotes: 9

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