Reputation: 19
Hello I want to get xml from Google Weather
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp= new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET", "http://www.google.com/ig/api?weather=london&hl=en", true);
xmlhttp.send(null);
xmlDoc=xmlhttp.responseXML;
It`s not working . Thanks
Upvotes: 0
Views: 5155
Reputation: 19
Ok here is the code :
<html>
<body>
<script type="text/javascript">
var xmlhttp;
var xmlDoc;
function callback(xhr)
{
xmlDoc = xhr.responseXML;
// further XML processing here
}
if (window.XMLHttpRequest)
{
xmlhttp = new XMLHttpRequest();
}
else
{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET", "http://www.google.com/ig/api?weather=london&hl=en", true);
xmlhttp.onreadystatechange = function ()
{
if (xmlhttp.readyState != 4) return;
if (xmlhttp.status != 200 && xmlhttp.status != 304) return;
callback(xmlhttp);
};
xmlhttp.send(null);
alert(xmlDoc);
</script>
</body>
</html>
It doesn`t returns any errors but alert returns undefined.
Upvotes: -1
Reputation: 1776
You can't do this via javascript to to it being a cross-domain request. You'd have to do this server-side.
In PHP you'd use CURL.
What you are trying to do can't be done with Javascript.
Upvotes: -1
Reputation: 360046
XMLHttpRequest
is asynchronous. You need to use a callback. If you don't want to use a full-fledged library, I recommend using Quirksmode's XHR wrapper:
function callback(xhr)
{
xmlDoc = xhr.responseXML;
// further XML processing here
}
sendRequest('http://www.google.com/ig/api?weather=london&hl=en', callback);
If you absolutely insist on implementing this yourself:
// callback is the same as above
var xmlhttp;
if (window.XMLHttpRequest)
{
xmlhttp = new XMLHttpRequest();
}
else
{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET", "http://www.google.com/ig/api?weather=london&hl=en", true);
xmlhttp.onreadystatechange = function ()
{
if (xmlhttp.readyState != 4) return;
if (xmlhttp.status != 200 && xmlhttp.status != 304) return;
callback(xmlhttp);
};
xmlhttp.send(null);
As @remi commented:
I think you'll get a cross domain access exception : you can't make an ajax request to an other domain than your page's. no ?
Which is (for the most part) correct. You'll need to use a server-side proxy, or whatever API that Google provides, instead of a regular XHR.
Upvotes: 3