CODEWITHSUNDEEP
pythondatetime
Glenn Ford
Glenn Ford

Reputation: 45

AttributeError: 'list' object has no attribute 'time'

AttributeError: 'list' object has no attribute 'time'

SO i want this list of list timeList = [ [ ],[ ],[ ] ] to store my firstTime, secondtime and thirdTime but it throws me an error. any idea on this

from datetime import datetime, date,timedelta

timeList = [[],[],[]]
timeList[1].append(datetime.now())
secondTime=timeList[1].time() # throws an error 
print(secondTime)

Upvotes: 1

Views: 2941

Answers (3)

Henry Bass
Henry Bass

Reputation: 19

you need to give the location of the item by saying where in the list you want to find it, and then look inside that sub-list. this works:

from datetime import datetime, date,timedelta
timeList = [[],[],[]]
timeList[1].append(datetime.now())
secondTime=timeList[1][0].time() # throws an error 
print(secondTime)

Upvotes: 0

SpiderPig1297
SpiderPig1297

Reputation: 335

Your problem is that timeList is a list of lists, hence every item in it is from type list.

When your run:

secondTime=timeList[1].time()

You are accessing the second item of timeList, which is a list itself, and trying to call time.

Try the following line instead:

secondTime=timeList[1][0].time()

Upvotes: 0

J_H
J_H

Reputation: 20450

You want this:

>>> secondTime = timeList[1][0].time() 
>>>
>>> timeList
[[], [datetime.datetime(2020, 10, 2, 17, 38, 12, 274423)], []]
>>> 
>>> timeList[1]
[datetime.datetime(2020, 10, 2, 17, 38, 12, 274423)]
>>> 
>>> secondTime
datetime.time(17, 38, 12, 274423)

Upvotes: 1

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