CODEWITHSUNDEEP
pythonarrayslistcombinations
meowulf
meowulf

Reputation: 377

Looping through combination of each paired element in python list

I have a list l = ['a', 'b', 'c'] and I want to loop through the combination (order doesn't matter) of each paired elements of l. Doing

import itertools
l= ['a', 'b', 'c']
for pair in itertools.product(l, l):
    print(pair)

yields:

('a', 'a')
('a', 'b')
('a', 'c')
('b', 'a')
('b', 'b')
('b', 'c')
('c', 'a')
('c', 'b')
('c', 'c')

but I want something like:

('a', 'a')
('a', 'b')
('a', 'c')
('b', 'b')
('b', 'c')
('c', 'c')

where the combinations like ('a', 'b') and ('b', 'a') doesn't repeat. what is the best way to do this?

Upvotes: 0

Views: 83

Answers (2)

wasif
wasif

Reputation: 15478

Try this:

arr=['a', 'b', 'c']
for i in range(len(arr)):
  for x in arr[i:]:
    print((arr[i],x))

Upvotes: 2

Frank Yellin
Frank Yellin

Reputation: 11285

import itertools
l = ['a', 'b', 'c']
for pair in itertools.combinations_with_replacement(l, 2):
    print(pair)

Upvotes: 3

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