Reputation: 133
I am using this for audio records and video file and it is working but i want to replace it with OkHttp. I didnt figure it out. Can anyone help me about it?
public class HttpMultipartUpload {
static String lineEnd = "\r\n";
static String twoHyphens = "--";
static String boundary = "AaB03x87yxdkjnxvi7";
public static String upload(URL url, File file, String fileParameterName, HashMap<String, String> parameters)
throws IOException {
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream dis = null;
FileInputStream fileInputStream = null;
byte[] buffer;
int maxBufferSize = 20 * 1024;
try {
//------------------ CLIENT REQUEST
fileInputStream = new FileInputStream(file);
// open a URL connection to the Servlet
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + fileParameterName
+ "\"; filename=\"" + file.toString() + "\"" + lineEnd);
dos.writeBytes("Content-Type: text/xml" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
buffer = new byte[Math.min((int) file.length(), maxBufferSize)];
int length;
// read file and write it into form...
while ((length = fileInputStream.read(buffer)) != -1) {
dos.write(buffer, 0, length);
}
for (String name : parameters.keySet()) {
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + name + "\"" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(parameters.get(name));
}
// send multipart form data necessary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
} finally {
if (fileInputStream != null) fileInputStream.close();
if (dos != null) dos.close();
}
//------------------ read the SERVER RESPONSE
try {
dis = new DataInputStream(conn.getInputStream());
StringBuilder response = new StringBuilder();
String line;
while ((line = dis.readLine()) != null) {
response.append(line).append('\n');
}
return response.toString();
} finally {
if (dis != null) dis.close();
}
}
}
How can I change it with OkHttp. Any code please. I dont have good knowledge about on OkHttp. I was using (HttpURLConnection) but it seems not effective now.
Upvotes: 1
Views: 1323
Reputation: 13448
See the documentation example on posting form data
RequestBody requestBody = new MultipartBody.Builder()
.setType(MultipartBody.FORM)
.addFormDataPart("title", "Square Logo")
.addFormDataPart("image", "logo-square.png",
RequestBody.create(
new File("docs/images/logo-square.png"),
MEDIA_TYPE_PNG))
.build();
Request request = new Request.Builder()
.header("Authorization", "Client-ID " + IMGUR_CLIENT_ID)
.url("https://api.imgur.com/3/image")
.post(requestBody)
.build();
Upvotes: 3