CODEWITHSUNDEEP
flutterdart
Sam324
Sam324

Reputation: 309

private named parameter in dart

I am new to Dart. Let's say I have a final List <Character> _characterList; which should be private. But how do I use CharacterList ({Key key, this._characterList}): super (key: key); if the named parameter cannot start with _?

Upvotes: 8

Views: 4563

Answers (2)

jamesdlin
jamesdlin

Reputation: 90005

The name of the parameter is independent of the name of the member. Constructors offer the this.name syntactic sugar for convenience if the names happen to be the same, but you don't have to use that. You could give the parameter its own name and explicitly initialize the member variable separately:

CharacterList({Key? key, required List<Character> characterList})
  : _characterList = characterList,
    super(key: key);

final List<Character> _characterList;

Upvotes: 15

Pavel Shastov
Pavel Shastov

Reputation: 3007

It is Dart limitation

Named optional parameters can't start with an underscore

You can use a constructor with optional positional parameter instead

CharacterList (Key key, [this._characterList]): super (key: key)

Upvotes: 1

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