CODEWITHSUNDEEP
python
Johnn Kaita
Johnn Kaita

Reputation: 452

Get the sum of product of 2 position values in every list within a dictionary

I have a dictionary that contains lists in it like the one below:

a = {'Dairy-Milk': ['Dairy-Milk', '12345', '800', 1], 'test': ['test', '1111', '600', 1]}

I want to go through the dictionary perform multiplication for (each_dictionary_Item[2] * each_dictionary_Item[3]) then get the total sum from all the items.

From my little knowledge, I have called a.get_keys then I have gone through for each item in the key,and called list pos 2 * 3, then appended that to another list in which I get the sum of the entire list using sum(list)....this gives me incorrect sums when new items are added.

 for item in self.listofKeys:
            thequantity = self.productList[item][3]
            thecash = self.productList[item][2]
            multiplied = float(thequantity) * float(thecash)
            self.thesumsList.append(multiplied)

        self.ids.thetotal.text = "Total Payable: " + str(sum(self.thesumsList))

Is there a cleaner way to achieve what I want? (get sum of every item in list list[3] * list[3])

Upvotes: 0

Views: 33

Answers (1)

Prune
Prune

Reputation: 77857

Yes: iterate over the values themselves, pulling out the desired product from each. Feed that result to sum directly as a generator.

sum(entry[2] * entry[3] for entry in a.values())

Upvotes: 2

Related Questions