CODEWITHSUNDEEP
angularformsdrop-down-menuhtml-selectangular2-ngmodel
Shiladitya Bose
Shiladitya Bose

Reputation: 1183

Angular option with ngModel does not display default option when paired with the value property

I have a list of types in my component.ts as followed.

  public type: string;
  types:Array<Object> = [
      {name: "Category", value: "c"},
      {name: "Cuisine", value: "a"},
      {name: "Main Ingredient", value: "i"},
  ];

And here is the corresponding HTML code.

<select class="form-control" id="queryTypeSelect" [(ngModel)]="type" name="queryTypeSelectForm"> 
    <option *ngFor="let typ of types" [value]="typ.value">{{ typ.name }}</option>
</select>

In the constructor, I have initialized "type" like this:

  constructor(
    private recipeService: RecipeService, 
    private apiService: ApiService) { 
      this.type = this.types[0]["name"];

  }

But when loading the page, the select bar shows nothing, until I manually select something. Although when selecting, the default item shows as checked (the first entry).

Why is this happening? When I remove the value property from the option, it shows the default entry alright. But I need to have the value property.

What is going wrong here? Any kind of help would be appreciated.

Upvotes: 0

Views: 49

Answers (2)

JWP
JWP

Reputation: 6963

<select class="form-control" id="queryTypeSelect"  name="queryTypeSelectForm"> 
    <option *ngFor="let typ of types"    
            [selected]="typ.name === type"
            [ngValue]="typ.value"
   >{{ typ.name }}</option>
</select>

Upvotes: 0

nrausch
nrausch

Reputation: 172

In your constructor, you should use this.type = this.types[0]["value"];

Angular Forms will compare ther Selects ngModel with each options [value] to select the preselected option.

While you use types[0]["name"], Angular has no chance to match your preselected value with the correct option.

Upvotes: 1

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