CODEWITHSUNDEEP
pythondjangodjango-views
naive_user
naive_user

Reputation: 119

Return location header in Django

I am writing an API for shortening URL and I have to return the following response.

request:
GET /:shorten_url
Content-Type: "application/json"

Expected Response:

302 response with the location header pointing to the shortened URL
HTTP/1.1 302 Found
Location: http://www.example.com # original url

I tried:

# shortcode is the shorten url of original url
def get(self, request, shortcode):
    if shortcode:
        try:
            shortUrl = UrlShort.objects.get(shortcode=shortcode)
            originalUrl = shortUrl.url
            response = HttpResponse(status=status.HTTP_302_FOUND)
            response['Location'] = shortUrl.url
            return response

        except UrlShort.DoesNotExist:
            raise Http404()

Rather than getting 302 status code with location header, I'm redirected to the url with status code 200. What is wrong in my code?

Upvotes: 0

Views: 360

Answers (1)

Charnel
Charnel

Reputation: 4432

There is special class for "found" redirect you can use - HttpResponseRedirect redirect instead:

...
return HttpResponseRedirect(shortUrl.url)

Upvotes: 2

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