Reputation: 137
PHP Form
<form id="f1" action="welcome.php" method="post">
Name: <input type="text" name="name"><br>
E-mail: <input type="text" name="email"><br>
<input name="btnSubmit" id="btnSubmit" type="submit">
</form>
PHP Post
if($_SERVER["REQUEST_METHOD"] == "POST")
{
if (isset($_POST['btnSubmit'])) {
echo 'You have clicked submit button';
}
}
Here the value is printing. But when we submit the form using the jquery:
$('#btnSubmit').on('click',function(e){
e.preventDefault();
var form = $(this).parents('form');
swal({
title: "Are you sure?",
text: "You will not be able to recover this imaginary file!",
type: "warning",
showCancelButton: true,
confirmButtonColor: "#DD6B55",
confirmButtonText: "Yes, delete it!",
closeOnConfirm: false
}, function(isConfirm){
if (isConfirm) form.submit();
});
});
The echo value is not printing. How can I print the echo value using jquery form submit?
SweetAlert: https://sweetalert.js.org/guides/
Upvotes: 0
Views: 165
Reputation: 4425
Try this;
if($_SERVER["REQUEST_METHOD"] == "POST")
{
print_r($_POST);
}
To see if you get value for btnSubmit
. Pretty sure you need to attach value for it to set a key/value pair in the $_POST.
The easiest way to make this work is to change your button to this:
<input name="btnSubmit" id="btnSubmit" type="submit" value="Submit">
The security issues presented when you don't check input are huge. Just check out Johnny Tables (https://xkcd.com/327/)
Upvotes: 0
Reputation: 426
btnSubmit
is not on your $_POST
variable;
only type text (in your case) is.
Upvotes: 0