CODEWITHSUNDEEP
bashshellunix
kilmonger
kilmonger

Reputation: 51

cannot open No such file or directory

I am trying to store the output of total count to a variable and then print the variable.

for i in `cat /home/retailer.sh`;do file = "$(grep $i /home/DD.inventory.loaded_master_list.txt|sort -u|wc -l)";echo $file;done

/home/retailer.sh
HAG
GAT

/home/DD.inventory.loaded_master_list.txt

/dailydata_hershey/prd/work/all/2109/delivery/POSDATA_FINAL.GAT.20200201.dat /dailydata_hershey/prd/work/all/2109/delivery/POSDATA_FINAL.HAG.20200201.dat

Below error i get =: cannot open = (No such file or directory)

Upvotes: 0

Views: 3513

Answers (1)

0x5453
0x5453

Reputation: 13589

file = "$(...)" - you have to use file="$(...)" (no spaces).

Otherwise it will be interpreted as a command. (e.g. file with an argument of =)

For future reference, shellcheck.net is a great resource for catching these kinds of things. Just copy-paste your script into the box and it will tell you all of the errors, how to fix them, and a handful of other warnings about potential bugs.

Upvotes: 1

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