Reputation: 77
In Notepad++ i have a text something like this:
https://i.sstatic.net/5nMhH.png
I want to select all lines with regex, which contains string "EMPLOYEES" and ends with ";"
Text to be selected:
EMPLOYEE_ID NUMBER(6,0) NOT NULL,
FIRST_NAME VARCHAR2(20) NULL,
LAST_NAME VARCHAR2(25) NOT NULL,
EMAIL VARCHAR2(25) NOT NULL,
PHONE_NUMBER VARCHAR2(20) NULL,
HIRE_DATE DATE NOT NULL,
JOB_ID VARCHAR2(10) NOT NULL,
SALARY NUMBER(8,2) NULL,
COMMISSION_PCT NUMBER(2,2) NULL,
MANAGER_ID NUMBER(6,0) NULL,
DEPARTMENT_ID NUMBER(4,0) NULL);
COMMENT ON TABLE EMPLOYEES IS
'employees table. Contains 107 rows. References with departments,
jobs, job_history tables. Contains a self reference.';
It works when there is only one line, for example:
https://i.sstatic.net/vmwYO.png
...but i want to select lines mentioned above (contains a specific word ("EMPLOYEES") and ends with specific char (";"))
Upvotes: 1
Views: 1328
Reputation: 521379
Try the following regex search in Notepad++:
Find: ^.*\bEMPLOYEES[\s\S]*?;
Explanation:
^ from the start of the line
.* match all content in that line until reaching
\b a word boundary
EMPLOYEES followed by 'EMPLOYEES'
[\s\S]*? match all content, this time across newlines, until reaching
; the nearest semicolon
Upvotes: 1