Reputation: 33
I need to do this:
table 1:
ID Cod.
1 20
2 102
4 30
7 10
9 201
10 305
table 2:
ID Cod.
1 20
2 50
3 15
4 30
5 25
7 10
10 300
Now, I got a table like this with an outer join:
ID Cod. ID1 Cod1.
1 20 1 20
2 50 . .
. . 2 102
3 15 . .
4 30 4 30
5 25 . .
7 10 7 10
. . 9 201
10 300 . .
. . 10 305
Now I want to add a flag that tell me if the ID have common values, so:
ID Cod. ID1 Cod1. FLag_ID Flag_cod:
1 20 1 20 0 0
2 50 . . 0 1
. . 2 102 0 1
3 15 . . 1 1
4 30 4 30 0 0
5 25 . . 1 1
7 10 7 10 0 0
. . 9 201 1 1
10 300 . . 0 1
. . 10 305 0 1
I would like to know how can I get the flag_ID, specifically to cover the cases of ID = 2 or ID=10.
Thank you
Upvotes: 1
Views: 33
Reputation: 27508
You can group by a coalescence of id
in order to count and compare details.
Example
data table1;
input id code @@; datalines;
1 20 2 102 4 30 7 10 9 201 10 305
;
data table2;
input id code @@; datalines;
1 20 2 50 3 15 4 30 5 25 7 10 10 300
;
proc sql;
create table got as
select
table2.id, table2.code
, table1.id as id1, table1.code as code1
, case
when count(table1.id) = 1 and count(table2.id) = 1 then 0 else 1
end as flag_id
, case
when table1.code - table2.code ne 0 then 1 else 0
end as flag_code
from
table1
full join
table2
on
table2.id=table1.id and table2.code=table1.code
group by
coalesce(table2.id,table1.id)
;
You might also want to look into
Proc COMPARE
with BY
Upvotes: 1