Reputation: 838
in F#, How to make a function wrapper (x:'T)
to wrap any inputs to an array of array, say: wrapper(1) = [|[|1|]|]; wrapper([|1|]) = [|[|1|]|]; and wrapper([|[|1|]|]) = [|[|1|]|];
something like below does not work:
let wrapper (x:'T) =
let y =
if not <| x.GetType().IsArray then [|[|x|]|]
elif not <| x.[0].GetType().IsArray then [|x|]
else x
y
Upvotes: 0
Views: 276
Reputation: 33657
You function needs to "wrap any inputs to an array of array". As par this statement the solution is as simple as:
let wrapper (x:'T) = [|[|x|]|];
But then the examples you have given are not as par your function definition.
i.e wrapper([|1|]) = [|[|1|]|]
should be wrapper([|1|]) = [|[|[|1|]|]|]
as par your function definition.
Upvotes: -1
Reputation: 22307
Here's a reflection based solution which will accept inputs of arbitrary nested array depth:
open System.Text.RegularExpressions
let wrapper input =
let ty = input.GetType()
if ty.IsArray |> not then
[|[|input |> unbox|]|]
else
let depth = Regex.Matches(ty.Name, "\[\]", RegexOptions.Compiled).Count
let rec findInnerItem curDepth curArray =
let innerItem = curArray.GetType().GetMethod("Get").Invoke(curArray, [|box 0|])
if curDepth = depth then
innerItem
else
findInnerItem (curDepth+1) innerItem
let innerItem = findInnerItem 1 input
[|[|innerItem |> unbox|]|]
Usage in FSI:
val wrapper : 'a -> 'b [] []
> let x : int[][] = wrapper 1;;
val x : int [] [] = [|[|1|]|]
> let x : int[][] = wrapper [|1|];;
val x : int [] [] = [|[|1|]|]
> let x : int[][] = wrapper [|[|1|]|];;
val x : int [] [] = [|[|1|]|]
> let x : int[][] = wrapper [|[|[|1|]|]|];;
val x : int [] [] = [|[|1|]|]
> let x : int[][] = wrapper [|[|[|[|1|]|]|]|];;
val x : int [] [] = [|[|1|]|]
> let x : int[][] = wrapper [|[|[|[|[|1|]|]|]|]|];;
val x : int [] [] = [|[|1|]|]
> let x : int[][] = wrapper [|[|[|[|[|[|1|]|]|]|]|]|];;
val x : int [] [] = [|[|1|]|]
Upvotes: 2
Reputation: 47914
The following seems to work:
let wrapper<'a, 'b> (x:'a) =
match box x with
| null -> null
| :? array<array<'b>> as y -> y
| :? array<'b> as y -> [|y|]
| y -> [|[|unbox y|]|]
The signature is 'a -> array<array<'b>>
.
In response to your comment: this sort of thing can be done in statically-typed languages--and, arguably better than in a dynamic language--but/because stepping outside the type system must be explicit (e.g., box
/unbox
).
Upvotes: 4
Reputation: 118895
You can't, that's not a well-typed function (try to write out the type signature).
Upvotes: 1