Reputation: 23737
I have this code:
import imaplib, re
import os
import time
conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("ddd", "dddd")
while(True):
unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
print unreadCount
if int(unreadCount) > 10:
print "restarting..."
time.sleep(50)
Which sometimes loses the connection and stops working. How can I catch the exception and start the code over every time it breaks?
Thanks
Upvotes: 0
Views: 1722
Reputation: 14900
Try this:
import imaplib, re
import os
import time
for n in range(3):
try:
conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("ddd", "dddd")
while(True):
unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
print unreadCount
if int(unreadCount) > 10:
print "restarting..."
time.sleep(50)
break
except Exception, e:
if n == 2:
print >>sys.stderr, "Failure During processing, restarting..."
print >>sys.stderr, e
You can set n to be however many tries you want to allow.
EDIT: Hmm, after further perusal, it seems I got your code slightly wrong. I've edited and fixed my version. You will need to adjust and edit your while loop, as I am not entirely sure what it is you are up to.
EDIT 2: Since you need to reconnect and try again, I've moved the conn section within the try block.
Upvotes: 0
Reputation: 12806
Use try ... except
try:
unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
if int(unreadCount) > 10:
print "restarting..."
time.sleep(50)
except Exception:
pass
Upvotes: 0
Reputation: 19513
import imaplib, re
import os
import time
while True:
try:
conn = imaplib.IMAP4_SSL("imap.gmail.com", 993)
conn.login("ddd", "dddd")
while True :
unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1)
print unreadCount
if int(unreadCount) > 10:
print "restarting..."
time.sleep(50)
except HypotheticalException:
pass
Upvotes: 4