Reputation: 33
I have 4 menus and with this piece of code, i can show menus and hide them with specific btns .my question is how can i when i open a menu and i don't close it and then I open another one close previous menus? i tried to store the open menu in a variable and check it when i open another one but it didn't work.
<body>
<div class="container">
<div class="menu">
<button class="btn">open</button>
<div class="items">
<div class="items-container">
<div class="item">item 1</div>
<div class="item">item 2</div>
<div class="item">item 3</div>
<div class="item">item 4</div>
<div class="item">item 6</div>
</div>
</div>
</div>
<div class="container">
<div class="menu">
<button class="btn">open</button>
<div class="items">
<div class="items-container">
<div class="item">item 1</div>
<div class="item">item 2</div>
<div class="item">item 3</div>
<div class="item">item 4</div>
<div class="item">item 6</div>
</div>
</div>
</div>
<div class="container">
<div class="menu">
<button class="btn">open</button>
<div class="items">
<div class="items-container">
<div class="item">item 1</div>
<div class="item">item 2</div>
<div class="item">item 3</div>
<div class="item">item 4</div>
<div class="item">item 6</div>
</div>
</div>
</div>
<div class="container">
<div class="menu">
<button class="btn">open</button>
<div class="items">
<div class="items-container">
<div class="item">item 1</div>
<div class="item">item 2</div>
<div class="item">item 3</div>
<div class="item">item 4</div>
<div class="item">item 6</div>
</div>
</div>
</div>
</div>
</body>
const btns = document.querySelectorAll(".btn");
btns.forEach(btn => {
const menu = btn.parentElement;
const items = menu.querySelector(".items");
const itemsContainer = items.querySelector(".items-container");
const itemsContainerHeight = itemsContainer.getBoundingClientRect().height;
let previousActivebtn = "";
btn.addEventListener("click", (e) => {
// change btn text
if (e.currentTarget.innerHTML == "open") {
e.currentTarget.innerHTML = "close";
} else {
e.currentTarget.innerHTML = "open";
}
//show and hid the menus
if (!items.classList.contains("item-active")) {
items.classList.add("item-active");
items.style.height = itemsContainerHeight + 32 + "px";
} else {
items.classList.remove("item-active");
items.removeAttribute("style");
}
});
});
Upvotes: 2
Views: 842
Reputation: 77045
You overcomplicate it. You could create a CSS rule which would ensure that .items
is hidden, unless .menu
is opened:
.menu .items:not(.open) {
display: none
}
And you could create a function like this:
function open(item) {
if (!item.classList.contains("open")) {
//Hide whatever was opened
for (let it of document.querySelectorAll(.menu .items.open)) {
it.classList.remove("open")
}
item.classList.add("open");
} else {
item.classList.remove("open");
}
}
Just pass to this function the item having the class of items
.
Upvotes: 2