Reputation: 62419
I am stuck with the ObjectBox Like Query. I have done as below when I search for something.
QueryBuilder<MItemDetail> builder = mItemDetailListBox.query();
builder.contains(MItemDetail_.productName, search);
itemList = builder.build().find();
For example, My data is:
Now as you know the contains works simply as that returns a list of items that contain a given search string.
If I search para new, I want the result paracetamol_new
If I search para p, I want the result paracetamol potest
If I search para e e, I want the result paracetamol potest and paracetamol_new
Is there any function or utility available in ObjectBox that can help me to achieve this?
Do let me know If you have any questions.
The given links in a comment, My question is different. I know all the methods contains()
, startsWith
, and endsWith
but my problem not getting solved using that.
Upvotes: 0
Views: 354
Reputation: 62419
With Reference to this answer I have done some changes as given and I got a perfect solution as I wanted.
QueryBuilder<MItemDetail> builder = mItemDetailListBox.query();
// builder.contains(MItemDetail_.productName, search);
builder.filter(new QueryFilter<MItemDetail>() {
@Override
public boolean keep(@NonNull MItemDetail entity) {
return like(entity.getProductName(), "%"+ search + "%");
}
}).order(MItemDetail_.productName);
businessModels = builder.build().find();
In the following methods, I have added one more replace statement .replace(" ",".*?")
private static boolean like(final String str, final String expr) {
String safeString = (str == null) ? "" : str;
String regex = quoteMeta(expr);
regex = regex.replace("_", ".").replace(" ",".*?").replace("%", ".*?");
Pattern p = Pattern.compile(regex,
Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
return p.matcher(safeString).matches();
}
private static String quoteMeta(String s) {
if (s == null) {
throw new IllegalArgumentException("String cannot be null");
}
int len = s.length();
if (len == 0) {
return "";
}
StringBuilder sb = new StringBuilder(len * 2);
for (int i = 0; i < len; i++) {
char c = s.charAt(i);
if ("[](){}.*+?$^|#\\".indexOf(c) != -1) {
sb.append("\\");
}
sb.append(c);
}
return sb.toString();
}
Thank you.
Upvotes: 1