CODEWITHSUNDEEP
php
Gurnor
Gurnor

Reputation: 339

Storing button inside of php variable

I have following code:

$boxId = 1;
$explainationBox='<input type="button" id="<?php echo $boxId; ?>" value="send" onmousedown="javascript:callthis(<?php echo $buttonId; ?>);" class="button" />';
                  echo $explainationBox;

I am trying to save these values as html button inside of php variable explainationBox. But its not saving actual value of $boxId. It is just saving it as $boxId. As boxId is inside a for loop and will keep on changing. How can i do this?

Upvotes: 1

Views: 993

Answers (4)

Gurnor
Gurnor

Reputation: 339

This code is working: $boxId = 1; $explainationBox=''; echo $explainationBox;

except for: "javascript:callthis('.$buttonId.');" call. In order to make this whole code work here is a solution for those who are looking:

$boxId = 1; $explainationBox=''; echo $explainationBox;

Upvotes: 0

meteorainer
meteorainer

Reputation: 952

You may find it useful to enter and exit the php environment within the loop so you don't have so save that string as a variable at all. 

for($i=1; $i<10; $i++){?>
     <input type="button" id="ID<?=$i?>" value="send"
       onmousedown="javascript:callthis('<?=$i?>');" class="button" />
<?php } ?>

So what we are doing is leaving the php environment as we open the loop (?>) then we give some raw html that will be plopped into the page as shown, no variable needed. Then while we are outside the php environment we use the <?= $variable ?> syntax to drop a php variable into the html language. And finally we re-enter the php environment by reopenning the php tags (<?php).

Note: That last ?> would go wherever you wanted to re-exit php again.

Upvotes: 0

alex
alex

Reputation: 490153

PHP tags in a string are not parsed (unless given to some functions such as eval()).

Use string concatenation.

Change this...

"<?php echo $boxId; ?>"

...to...

"' . $boxId . '"

Upvotes: 0

Shakti Singh
Shakti Singh

Reputation: 86346

You do not nedd <?php tag when this tag is already opened

Try this

$boxId = 1;
$explainationBox='<input type="button" id="'.$boxId.'" value="send"
           onmousedown="javascript:callthis('.$buttonId.');" class="button" />';
echo $explainationBox;

Upvotes: 2

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