Reputation: 187
I've implemented the Caesar's cipher in C, and, despite the algorithm is working, I didn't understood why (sometimes) I get an empty value if I do not subtract the first letter of the alphabet before adding the key. Here's the full code (see line 59 or search for return (letter + k) % 26
):
#include <cs50.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
string caesar_cipher(string text, int k);
char replace_letter(char letter, int k);
bool is_numeric(string input);
int main(int argc, string argv[])
{
if (argc != 2 || (argc == 2 && !is_numeric(argv[1])))
{
fprintf(stderr, "You must specify a key to the cipher! Exiting...\n");
exit(EXIT_FAILURE);
}
// Convert command line argument to integer.
int k = atoi(argv[1]);
// Prompts user for the text to encrypt
string text = get_string("plaintext: ");
// Returns encrypted text
printf("ciphertext: %s\n", caesar_cipher(text, k));
exit(EXIT_SUCCESS);
}
string caesar_cipher(string text, int k)
{
int text_length = strlen(text);
string ciphered_text = text;
for (int i = 0; text[i] != '\0'; i++)
{
ciphered_text[i] = replace_letter(text[i], k);
}
return ciphered_text;
}
char replace_letter(char letter, int k)
{
// Early return when 'letter' is a non-alphabetical character
if (!isalpha(letter))
{
return letter;
}
char operation_letter = 'a';
if (isupper(letter))
{
operation_letter = 'A';
}
// return (letter + k) % 26; // Sometimes, returns an empty value
return ((letter - operation_letter + k) % 26) + operation_letter;
}
// Loop over characters to check if each one of them is numeric
bool is_numeric(string input)
{
for (int i = 0; input[i] != '\0'; i++)
{
// If character is not numeric
// returns false.
if (isdigit(input[i]) == 0)
{
return false;
}
}
return true;
}
Can anybody explain why this happens?
Upvotes: 0
Views: 57
Reputation: 131
You need to account for the first letter of the alphabet (either a
or A
) in your functions because char
s are internally represented as an integer number (usually only a single byte, but it depends on the encoding). In ASCII for example, doing a % 26
will result in any of the 26 first values of the ASCII table, none of which are actual letters. Hopefully I made myself clear.
Upvotes: 1