CODEWITHSUNDEEP
regexlinuxawksedscripting
Eren
Eren

Reputation: 21

Skipping a part of a line using sed

I have a file with content like so - @1: 00001109 Each line is of the same format. I want the final output to be @1: 00 00 11 09.

I used command in sed to introduce a space every 2 characters - sed 's/.\{2\}/& /g'. But that will give me spaces in the part before the colon too which I want to avoid. Can anyone advise how to proceed?

Upvotes: 0

Views: 182

Answers (4)

tshiono
tshiono

Reputation: 22042

If perl happens to be your option, how about:

perl -pe '1 while s/(\d+)(\d\d)/$1 $2/g' file

Upvotes: 1

user14262883
user14262883

Reputation:

you can use pure bash:

for line in "$(<your_file.txt)"; do
    first=`echo $line | cut -d' ' -f1`" "
    last=`echo $line | cut -d' ' -f2`
    for char in `seq 0 2 ${#last}`; do
        first+=${last:$char:2}" "
    done;
done;

Upvotes: 0

potong
potong

Reputation: 58488

This might work for you (GNU sed):

sed 's/[0-9][0-9]\B/& /g' file

After a pair of digits within a word, insert a space.

Upvotes: 2

RavinderSingh13
RavinderSingh13

Reputation: 133680

Could you please try following, written and tested with shown samples.

awk '{gsub(/../,"& ",$2);sub(/ +$/,"")} 1' Input_file

Explanation: First globally substituting each 2 digits pair with same value by appending space to it where gsub is globally substitution to perform it globally). Once this is done, using single sub to substitute last coming space with NULL to avoid spaces at last of lines.

With sed:

sed -E 's/[0-9]{2}/& /g;s/ +$//'  Input_file

Explanation: Globally substituting each pair of digits with its same value and appending spaces to it. Then substituting space coming last space of line(added by previous substitution) with NULL.

Upvotes: 2

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