CODEWITHSUNDEEP
pythonstringloopsindexing
Nick Perozzi
Nick Perozzi

Reputation: 3

Looping through a string, need the index of that string

Python novice. I'm looping through a string, and I need to be able to index the location of each character in the string. However, .index() just gives me the first time the character pops up, and I need the location of the exact character I'm looping through.

string = "AT ST!"
for i in string[1:]:
    ind = string.index(i)      #only finds first instance
    quote = string[ind-1] + i
    print(quote)

Let's say I want this to return

AT
T 
 S
ST   #what I want
T!

but instead it would return

AT
T 
 S
AT   #heck
T!

Any help would be appreciated!

Upvotes: 0

Views: 1131

Answers (4)

Shubham Chaudhary
Shubham Chaudhary

Reputation: 13

You could attain this by looping through the index position using the range and len functions in python like this:

string = "AT ST!"  
for i in range(len(string) - 1):  
    print(string[i]+string[i+1])

The .index() function is working as it is supposed to, it actually starts searching from the first index.

Upvotes: 0

Alam Sk
Alam Sk

Reputation: 11

In this kind of scenario its better not to use index as is suggested by schwobaseggl. But Just for the sake of using index in this example below is the way you can use it. index can take parameters of start and end index so it will only search between those indexes so you can pass the current index as starting index in this example.

list.index(element, start, end)

for ind,i in enumerate(string[1:],1):
    ind = string.index(i,ind)     
    quote = string[ind-1] + i
    print(quote)```

Upvotes: 0

rohit vinod
rohit vinod

Reputation: 1

Use the enumerate() method.

string = "AT ST!"
for i, s in enumerate(string[1:]:
    quote = string[i] + s
    print(quote)

Upvotes: 0

user2390182
user2390182

Reputation: 73470

You can use enumerate to iterate indeces and chars in parallel:

for ind, i in enumerate(string[1:], 1):
    quote = string[ind-1] + i
    print(quote)

Or even better, use slices:

for i in range(1, len(string)):
    print(string[i-1:i+1])

Upvotes: 2

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