CODEWITHSUNDEEP
javascriptecmascript-6lodash
Surya
Surya

Reputation: 35

compare multiple array of objects javascript with the value

let a = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'green'
}];
let b = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'brown'
}];
let c = [{
    isMatched: false,
    value: 'white'
}, {
    isMatched: false,
    value: 'green'
}];
let d = [{
    isMatched: false,
    value: 'red'
}, {
    isMatched: false,
    value: 'orange'
}];

// expected output

let a = [{
    isMatched: true,
    value: 'red'
} {
    isMatched: true,
    value: 'green'
}];
let b = [{
    isMatched: true,
    value: 'red'
}, {
    isMatched: false,
    value: 'brown'
}];
let c = [{
    isMatched: false,
    value: 'white'
}, {
    isMatched: true,
    value: 'green'
}];
let d = [{
    isMatched: true,
    value: 'red'
}, {
    isMatched: false,
    value: 'orange'
}];

Upvotes: 1

Views: 59

Answers (2)

Mo_-
Mo_-

Reputation: 634

You can combine all the arrays in one and then count the values that appear more than one:

let combinedArrays = a.concat(b, c, d);
countValues = {}

combinedArrays.forEach(function(v) {
  if (isNaN(countValues[v.value])) {
    countValues[v.value] = 1;
  }else {
    countValues[v.value] += 1;
  }
})

You can then iterate through each of the arrays and check if countValues[value] > 1 then set isMatched to true

Upvotes: 0

Nina Scholz
Nina Scholz

Reputation: 386604

You could take a Map, check if the map contains a data set with value as key and if not add the object to the map or set the stored object's isMatched property to true, as well as the actual object.

For preventing setting true to much the value is changed to undefined.

let a = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'green' }],
    b = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'brown' }],
    c = [{ isMatched: false, value: 'white' }, { isMatched: false,  value: 'green' }],
    d = [{ isMatched: false, value: 'red' }, { isMatched: false, value: 'orange' }];

[a, b, c, d].forEach((m => a => a.forEach(o => {
    if (m.has(o.value)) {
        o.isMatched = true;
        const temp = m.get(o.value);
        if (temp) {
            temp.isMatched = true;
            m.set(o.value, undefined);
        }
    } else {
        m.set(o.value, o);
    }
}))(new Map));

console.log(a);
console.log(b);
console.log(c);
console.log(d);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 2

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