Reputation: 47
suppose I have a lot of dataframe, with similar structure, but different columns. I want to combine all of them together, how to do it in a easier way?
for example, df1, df2, df3 are as follows:
df1
id base1 base2 col1 col2 col3 col4
1 1 100 30 1 2 3
2 2 200 40 2 3 4
3 3 300 20 4 4 5
df2
id base1 base2 col1
5 4 100 15
6 1 99 18
7 2 89 9
df3
id base1 base2 col1 col2
9 2 77 12 3
10 1 89 16 5
11 2 88 10 7
to be:
id base1 base2 col1 col2 col3 col4
1 1 100 30 1 2 3
2 2 200 40 2 3 4
3 3 300 20 4 4 5
5 4 100 15 NaN NaN NaN
6 1 99 18 NaN NaN NaN
7 2 89 9 NaN NaN NaN
9 2 77 12 3 NaN NaN
10 1 89 16 5 NaN NaN
11 2 88 10 7 NaN NaN
currently I use this code:
from pyspark.sql import SparkSession, HiveContext
from pyspark.sql.functions import lit
from pyspark.sql import Row
def customUnion(df1, df2):
cols1 = df1.columns
cols2 = df2.columns
total_cols = sorted(cols1 + list(set(cols2) - set(cols1)))
def expr(mycols, allcols):
def processCols(colname):
if colname in mycols:
return colname
else:
return lit(None).alias(colname)
cols = map(processCols, allcols)
return list(cols)
appended = df1.select(expr(cols1, total_cols)).union(df2.select(expr(cols2, total_cols)))
return appended
df_comb1=customUnion(df1,df2)
df_comb2=customUnion(df_comb1,df3)
however, if I keep creating new dataframe like df4,df5,etc. (100+) my code becomes messy.
is there a way to code it in a easier way?
Thanks in advance
Upvotes: 2
Views: 173
Reputation: 45339
You can manage this with a list of data frames and a function, without necessarily needing to statically name each data frame...
dataframes = [df1,df2,df3] # load data frames
Compute the set of all possible columns:
all_cols = {i for lst in [df.columns for df in dataframes] for i in lst}
#{'base1', 'base2', 'col1', 'col2', 'col3', 'col4', 'id'}
A function to add missing columns to a DF:
def add_missing_cols(df, cols):
v = df
for col in [c for c in cols if (not c in df.columns)]:
v = v.withColumn(col, f.lit(None))
return v
completed_dfs = [add_missing_cols(df, all_cols) for df in dataframes]
res = completed_dfs[0]
for df in completed_dfs[1:]:
res = res.unionAll(df)
res.show()
+---+-----+-----+----+----+----+----+
| id|base1|base2|col1|col2|col3|col4|
+---+-----+-----+----+----+----+----+
| 1| 1| 100| 30| 1| 2| 3|
| 2| 2| 200| 40| 2| 3| 4|
| 3| 3| 300| 20| 4| 4| 5|
| 5| 4| 100| 15|null|null|null|
| 6| 1| 99| 18|null|null|null|
| 7| 2| 89| 9|null|null|null|
| 9| 2| 77| 12| 3|null|null|
| 10| 1| 89| 16| 5|null|null|
| 11| 2| 88| 10| 7|null|null|
+---+-----+-----+----+----+----+----+
Upvotes: 1