CODEWITHSUNDEEP
xmlscalalift
aioobe
aioobe

Reputation: 420921

Variable in attribute value of XML-literal

I'm working with LiftWeb, XML and the bind method.

This works:

scala> val id = "test"                    
id: java.lang.String = test

scala> <a href={id}>link</a>              
res4: scala.xml.Elem = <a href="test">link</a>

but what if I want <a href="page?param=test">link</a>?

This doesn't work:

scala> <a href="page?param={id}">link</a>   
res5: scala.xml.Elem = <a href="page?param={id}">link</a>

Upvotes: 28

Views: 6575

Answers (3)

trupti rath
trupti rath

Reputation: 71

Using this , you won't miss the quotes : <a href={s"page?param=$Id"}>link</a>

Upvotes: 0

rumtscho
rumtscho

Reputation: 2524

The answer to put it all in curly braces is correct. But don't forget that you need to have a string in the curly braces!

So, you have to write something like (not your example, obviously)

<edge label={name} weight={weight.toString} />

If you come from a language which converts types for you, it can cost you a few minutes of head scratching before you remember what's wrong, because SBT offers no error message, just underlines it.

Upvotes: 2

Knut Arne Vedaa
Knut Arne Vedaa

Reputation: 15742

You put the whole thing inside the brackets:

<a href={ "page?param=" + id }>link</a>

Upvotes: 32

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