CODEWITHSUNDEEP
c++
Wieb Attema
Wieb Attema

Reputation: 25

Is it possible to put multiple names in one string?

I just started learning C++ and I'm currently following a tutorial on YouTube.

I thought it was fun to make a very simple 'access' program. If I type in my name it says, "Welcome!" If I type in another name it says, "access denied". It worked perfectly fine, but then I wanted the program to say "Welcome!" to two different names. So, I wanted to add a second name in the string, but I couldn't figure out how to do that. I googled a lot but I couldn't find anything. In the end, I came to string name = ("Joe", "Sean");, but here, it was only valid for Sean. I just can't figure out how to put multiple names in one string and make them both work. I hope you can help me, here is my code:

#include <iostream>
#include <cmath>
#include <string>

using namespace std;




int main()
{
    string name = ("Joe", "Sean");
    string input;
    cout << "What is your name?\nMy name is: ";
    cin >> input;



    if(input == name){
        cout << "Welcome, "<< input <<"! ";

    } else {
        cout << "Access denied";
    }



    
    return 0;
}

Upvotes: 1

Views: 1925

Answers (2)

gkaf
gkaf

Reputation: 94

The problem is in the string variable "name". You need an array of strings, not a single string.

This is an example implementation:

#include <iostream>
#include <cmath>
#include <string>

using namespace std;

int main()
{
    string names[] = {"Joe", "Sean"};

    string input;
    cout << "What is your name?\nMy name is: ";
    cin >> input;

    for (int i = 0; i < end(names) - begin(names); i++) {
      if(input == names[i]){
          cout << "Welcome, "<< input <<"! " << endl;
          return 0;
      }
    }

    cout << "Access denied" << endl;

    return 0;
}

You encountered some quirky features of C++ in the approach you are using to initialize your string variable:

string s1 = ("Joe"); // creates a string "Joe"
string s2 = ("Joe", "Sean"); // creates 2 strings, "Joe" and "Sean", and the variable s2 stores only the latter!

For more details on the different methods for initializing variables there has been an interesting discussion in this previous question.

Upvotes: 1

Sambalika
Sambalika

Reputation: 100

This is a way to do it using a vector of strings, so you can adapt easily with more names :

#include <iostream>
#include <vector>

using namespace std;

void printMessage(string message)
{
    std::cout << message << std::endl;
}

int main()
{
    vector<string> names{"Joe", "Sean", "Paul"};
    string input;
    cout << "What is your name? " << endl;
    cin >> input;

    for (string name : names)
    {
        if (name == input)
        {
            printMessage("Welcome!");
            return 0;
        }
    }
    printMessage("Access Denied!");

    return 0;
}

Upvotes: 2

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