Reputation: 11311
I am exporting my data into Excel Using Open XML
. now i want to increment of alphabet like as columns 'A1' to 'B1',...'Z1', 'AA1'.
I have assign 'A1' into variable and i want to increment alphabet to 'B1'.
Please provide any method/code through that can increment alphabet 'A1' to 'B1'..'Z1','AA1'.
Upvotes: 24
Views: 56474
Reputation: 1
Char does not allow more than one at a time. Single inside single quotes. char a=‘A’; Char b=‘1’; As character holds one character at a time in general.
Upvotes: 0
Reputation: 51
You can use string builder to achieve this.
int length = value.Length;
var lastString = value[length - 1];
if (lastString == 'Z')
{
if ((length - 2) >= 0)
++value[length - 2];
else
value.Append('A');
value.Replace("Z", "A");
}
else
++value[length - 1];
Upvotes: -1
Reputation: 61
This method will give you the next column:
private static Regex ALL_Z_REGEX = new Regex("^[zZ]+$");
static string GetNextColumn(string currentColumn)
{
// AZ would become BA
char lastPosition = currentColumn[currentColumn.Length - 1];
if (ALL_Z_REGEX.IsMatch(currentColumn))
{
string result = String.Empty;
for (int i = 0; i < currentColumn.Length; i++)
result += "A";
return result + "A";
}
else if (lastPosition == 'Z')
return GetNextColumn(currentColumn.Remove(currentColumn.Length - 1, 1)) + "A";
else
return currentColumn.Remove(currentColumn.Length - 1, 1) + (++lastPosition).ToString();
}
Upvotes: 0
Reputation: 12495
I think these function do what you want:
public static string IncrementXLColumn(string Address)
{
var parts = System.Text.RegularExpressions.Regex.Matches(Address, @"([A-Z]+)|(\d+)");
if (parts.Count != 2) return null;
return incCol(parts[0].Value) + parts[1].Value;
}
private static string incCol(string col)
{
if (col == "") return "A";
string fPart = col.Substring(0, col.Length - 1);
char lChar = col[col.Length - 1];
if (lChar == 'Z') return incCol(fPart) + "A";
return fPart + ++lChar;
}
This function would take a string of A1 to B1, Z1 to AA1 etc. Should cope with ZZ1 to AAA1 as well
Upvotes: 1
Reputation: 27923
This example uses an iterator capable of going from A
through ZZ
.
public static IEnumerable<string> GetColumns()
{
string s = null;
for (char c2 = 'A'; c2 <= 'Z' + 1; c2++)
{
for (char c = 'A'; c <= 'Z'; c++)
{
yield return s + c;
}
s = c2.ToString ();
}
}
This sample starts at A1
and goes through AA1
string currentCell = "A1";
int currentRow = int.Parse(Regex.Match(currentCell, @"\d+").Value);
string currentCol = Regex.Match(currentCell, @"[A-Z]+").Value;
foreach (string column in GetColumns().Where (c => c >= currentCol && currentCol <= "AA"))
{
Console.WriteLine (column + currentRow);
}
This sample starts at C5
and enumerates through the next 26 columns.
int columnsToAdd = 26;
currentCell = "C5";
currentRow = int.Parse(Regex.Match(currentCell, @"\d+").Value);
currentCol = Regex.Match(currentCell, @"[A-Z]+").Value;
foreach (string column in GetColumns().Where (c => c >= currentCol))
{
if (columnsToAdd--) == 0)
break;
Console.WriteLine (column + currentRow);
}
Upvotes: 4
Reputation: 5968
This can be done:
char c1 = 'A';
c1++; // c1 is 'B' now
and you can add the numbering as a string, even the concatenated characters can be generated the same way:
pseudo code:
If Reached_Z Then Add_Another_A
Upvotes: 60