Reputation: 75
I'm trying to count unique user ids in a log table by month. So far I came up with the following query:
SELECT
COUNT(CASE WHEN log_date LIKE '2020-01%' THEN 1 END) AS januari
FROM user_log;
This query returns the total of all rows of the user_log in januari. However I would like to know how many unique users have logged in in Januari. So I need something like:
SELECT
COUNT(**DISTINCT user_id** CASE WHEN log_date LIKE '2020-01%' THEN 1 END) AS januari
FROM user_log;
I also tried GROUP BY, but so far no luck. Does anyone have a suggestion?
Upvotes: 0
Views: 227
Reputation: 222572
Consider:
SELECT COUNT(DISTINCT CASE WHEN log_date >= '2020-01-01' AND log_date < '2020-02-01' THEN userid END) AS januari
FROM user_log;
I changed the filtering logic to use half-open intervals rather than string matching: it is more efficient.
Note that, if you just that result for January, it is sufficient to use a WHERE
clause:
SELECT COUNT(DISTINCT userid) januari
FROM user_log
WHERE log_date >= '2020-01-01' AND log_date < '2020-02-01'
Upvotes: 2