CODEWITHSUNDEEP
pythonlistintegertuples
chatshi
chatshi

Reputation: 13

Python : why results are same when i put int or list or tuple in list?

>>> aa = [10, 20, 30]
>>> aa[1:2] = 100, 200
[10, 100, 200, 30]

>>> aa = [10, 20, 30]
>>> aa[1:2] = [100, 200]
[10, 100, 200, 30]

>>> aa = [10, 20, 30]
>>> aa[1:2] = (100, 200)
[10, 100, 200, 30]

I'm a beginner to Python. I tried to change 20 into 100, 200, so I tried 3 ways of inserting these 2 numbers: ints, a list, and a tuple. Why is the result the same when I insert ints or a list or a tuple in aa[1:2]?

Upvotes: 1

Views: 29

Answers (1)

Hayley Guillou
Hayley Guillou

Reputation: 3973

By using aa[1:2], you are modifying a list item using slice assignment. Slice assignment replaces the specified item (or items), in this case the second item in aa, with whatever new item(s) that is specified. I'll go through each type to clarify what is happening

Ints - aa[1:2] = 100, 200: this example is the most clear. We are replacing aa[1:2] with two ints that go into the list in that spot.

List/Tuple: this example of how slice assignment works -- instead of adding a list to the list, it extends the new list into the old list. The tuple works the same way. To replace the item and add a list or tuple, wrap the list or tuple in another list first:

>>> aa = [10, 20, 30]
>>> aa[1:2] = [[100, 200]]
[10, [100, 200], 30]

>>> aa = [10, 20, 30]
>>> aa[1:2] = [(100, 200)]
[10, (100, 200), 30]

Upvotes: 1

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