CODEWITHSUNDEEP
pythonpython-3.x
pratap pudi
pratap pudi

Reputation: 13

How to find the odd numbers in a given range in Python?

Shown below is the code to print the odd numbers in a given range of integers.

When I'm using the return keyword, it's checking the 3 and returning the num, so the output is 3, but this is not the required output I'm looking for. The required output is 3,5.

In another case when I'm using the print function instead of return, the program checks 3,4,5 and returns '3 & 5' as the output.

Could help me to get the right output

def oddNumbers(l, r):

    # iterating each number in list
    for num in range(l, r + 1):

        # checking condition
        if num % 2 != 0:

            return num

Upvotes: 1

Views: 16471

Answers (3)

ayesha ayub
ayesha ayub

Reputation: 131

Simple solution using list comprehension:

def odd(l,u):
    return([a for a in range(l,u) if a%2 != 0])

Upvotes: 0

DYZ
DYZ

Reputation: 57033

There is no need to go through the range. Take a look at the first number: if it is odd, build a new range with the step of 2 that starts at that number. If it is even, then start at the next number.

def oddNumbers(l, r):
    if l % 2 == 1: 
        return list(range(l,     r + 1, 2))
    else: 
        return list(range(l + 1, r + 1, 2))

Or, in a more Pythonic way:

def oddNumbers(l, r):
    return list(range(l if l % 2 else l + 1, r + 1, 2))

Upvotes: 4

sophros
sophros

Reputation: 16640

You can use the following approach which stores the interim values in a list named odd and returns the list after going through the range of numbers between l and r:

def oddNumbers(l, r):
    odd = []
    # iterating each number in list
    for num in range(l, r + 1):

        # checking condition
        if num % 2 != 0:
            odd.append(num)
    return odd

Upvotes: 1

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