CODEWITHSUNDEEP
processing
Shay Boual
Shay Boual

Reputation: 23

Integers converted to strings do not work as expected

Issue comparing str() to what I'd expect is their String form

Code :

int i = 2;
String r = str(i);
println(r);
if (r == "2") {
  println("String works");
} else println("String doesnt work");
if (i == 2) {
  println("Integer works");
} else println("Integer doesnt work");

Prints :

2
String doesnt work
Integer works

The second if statement is a copy paste of the first, with only the variable and value changed so theres nothing wrong with my if statement

Processing documentation states (about str()):

Converts a value of a primitive data type (boolean, byte, char, int, or float) to its String representation. For example, converting an integer with str(3) will return the String value of "3", converting a float with str(-12.6) will return "-12.6", and converting a boolean with str(true) will return "true".

Also doesnt work with str(2) == "2" or str(i) == "2"

How do I fix this and get it to work (without converting it back to an integer because that would make my code a bit ugly)

Upvotes: 0

Views: 109

Answers (1)

Kevin Workman
Kevin Workman

Reputation: 42176

You should not compare String values using ==. Use the equals() function instead:

if (r.equals("2")) {

From the reference:

To compare the contents of two Strings, use the equals() method, as in if (a.equals(b)), instead of if (a == b). A String is an Object, so comparing them with the == operator only compares whether both Strings are stored in the same memory location. Using the equals() method will ensure that the actual contents are compared. (The troubleshooting reference has a longer explanation.)

More info here: How do I compare strings in Java?

Upvotes: 1

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