CODEWITHSUNDEEP
javascriptoopdom-events
Abhishek B.
Abhishek B.

Reputation: 5202

How can implement overloading in JavaScript/jQuery?

Im trying to call functions with same signature.

Example: There are two functions with same name:

<script>
    var obj1,obj2,obj3,obj4,obj5;
    function OpenBox(obj1,obj2){
    // code
    }
    function OpenBox(obj1,obj2,obj3,obj4,obj5){
    // code
    }
</script>

When I calling function on click event of link

<a id='hlnk1' href='#' onclick='OpenBox(this,\"abhishek\"); return false;'> Open Box </a>

When I click on the above link it is calling function OpenBox(obj1,obj2,obj3,obj4,obj5){}

It should be call function OpenBox(obj1,obj2){} Instead.

What's going wrong in functions?

Upvotes: 10

Views: 11498

Answers (7)

Yonatan Alexis Quintero Rodrig
Yonatan Alexis Quintero Rodrig

Reputation: 233

in the polymorphism you can use a different signature method ,in javascript we can simulate polymorphism checking the type of the function parameter and execute certain task.

var input = document.getElementById('data');
polymorphism(input);
polymorphism('Hello word 2');
polymorphism('hello word 3', 5);

function polymorphism(arg,arg1){ 
  var string = null;
  var sqr = 0;
  if(typeof arg === 'string'){
    string = 'arg type String: \n'+arg;
  }else if (arg.tagName && arg.tagName === 'INPUT'){
    string = 'arg type Input: \n'+arg.value;
  }
  if(arg1 && typeof arg1 === 'number'){
    sqr = arg1*arg1;
    alert(string + ' and sqr = '+sqr);
  }else {
    alert(string);
  }    
}

Check this example in JSFIDDLE

Upvotes: 3

Jacksonkr
Jacksonkr

Reputation: 32247

Once a function is defined in ecmascript, that name is locked. However, you can pass any number of parameters to that function so you do the rest of the work on the inside.

function foo(arg1, arg2) {
    // any code that is needed regardless of param count

    if(arg2 !== undefined) {
        // run function with both arguments
        console.log(arguments);
    } else if(arg1 !== undefined) {
        // run function with one argument
    } else {
        // run function with no arguments
    }
}

foo(1);
foo(1,2);
foo(1,2,3);

Interesting note: you can pass in extra parameters that aren't in the function declaration. Do a console.log of arguments and you'll see everything in there. arguments is an object which can be accessed like / typecasted to an array.

Upvotes: 2

Mikola
Mikola

Reputation: 9326

mattn has the correct idea. Because javascript has no typing those functions are equivalent. What you could do is something like this:

function OpenBox_impl1(obj1,obj2){
    // code
}
function OpenBox_impl2(obj1,obj2,obj3,obj4,obj5){
    // code
}

function OpenBox(obj1, obj2, obj3, obj4, obj5) {
    if(arguments.length == 2)
        return OpenBox_impl1(obj1, obj2);
    else
        return OpenBox_impl2(obj1,obj2,obj3,obj4,obj5);
}

Upvotes: 14

James Allardice
James Allardice

Reputation: 166031

You cannot overload functions in JavaScript. Instead, the most recently defined version of the function will be used, which is why in your case the version with 5 parameters is called (the final 3 are just undefined).

There are several ways around this, one if which is shown in Mikola's answer. An alternative is to pass in an object, and then check the contents of that object in the function (see this question):

function foo(a, b, opts) {

}

foo(1, 2, {"method":"add"});
foo(3, 4, {"test":"equals", "bar":"tree"});

Another option is to check arguments.length:

function foo(a, b) {
    if(arguments.length > 2) {
        var arg3 = arguments[3];
        //etc...
    }
}

Upvotes: 3

Joe Francis
Joe Francis

Reputation: 169

The issue is that you are trying to overload a function but that is not supported by Javascript. I think your best option is to use Polymorphism instead. View this article for more details: http://www.cyberminds.co.uk/blog/articles/polymorphism-in-javascript.aspx

Upvotes: 2

mattn
mattn

Reputation: 7733

javascript can't define duplicate function in same scope. check arguments.length are 2 or 5.

Upvotes: 6

kobe
kobe

Reputation: 15835

@abshik ,

There is nothing like that which is similar to c# or java. Javasccript behaves this way

function Test(arg1 ,arg2 , arg3, arg4)
{

}

when you are calling this function you can call in the following ways

Test(arg1);
Test(arg1,arg2);
Test(arg1,arg2,arg3);
Test(arg1,arg2,arg3,arg4);

But sequence matters , so you can the function in the above ways.

Upvotes: 2

Related Questions