CODEWITHSUNDEEP
pythonflask
The Trainer
The Trainer

Reputation: 695

Running flask script from parent directory

I have python script python_proj.py. There're few prints and simple functions. It calls a flask script:

os.system("flask run")

Flask script is in the same directory. Everything works when I run these from terminal in current directory:

user123@user123:~/PycharmProjects/python_and_bash$ ./python_proj.py

But when I'm in parent directory (for example '~') and I try to run this script:

user123@user123:~$ ./PycharmProjects/python_and_bash/python_proj.py

It doesn't work and gives me this error:

* Environment: production
WARNING: This is a development server. Do not use it in a production deployment.
Use a production WSGI server instead.
* Debug mode: off
Usage: flask run [OPTIONS]

Error: Could not locate a Flask application. You did not provide the "FLASK_APP" environment variable, and a "wsgi.py" or "app.py" module was not found in the current directory.

How to do it? I need to send this app for non-technical mates. It should work everywhere and everytime

Upvotes: 2

Views: 2527

Answers (2)

The Trainer
The Trainer

Reputation: 695

I added these lines in my proj_python.py script. Now it works.

 path = pathlib.Path(os.path.realpath(__file__))
 path = str(path.parent) + "/app.py"
 os.system(path)

Be aware! Don't put os.system("flask run") after these lines! It will cause that flask script will start 2 times! First start will be caused by: os.system(path), after ctrl+c or interrupt signal os.system("flask run") will start second time.

Upvotes: 0

YaTrippin
YaTrippin

Reputation: 56

You could find the absolute path of the directory of your script using this code:

import pathlib


parent_folder = pathlib.Path(__file__).parent.absolute() # Get the absolute path of parent folder

os.environ['FLASK_APP'] = parent_folder / 'your_flask_app.py' # Set environment variable
os.system("flask run")

Upvotes: 2

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