CODEWITHSUNDEEP
python-3.xstringconditional-statements
Shakiib
Shakiib

Reputation: 57

capitalizes sentence correctly in python

I want to write a program which takes a string as input and print a new copy of the string that has been correctly capitalized. My function should:

● Capitalize the first letter in the string
● Capitalize the first letter after a full-stop, exclamation mark or question mark
● Capitalize the word “i” if it is in lowercase.

Sample Input: my favourite animal is a dog. a dog has sharp teeth so that it can eat flesh very easily. do you know my pet dog’s name? i love my pet very much.

Sample Output: My favourite animal is a dog. A dog has sharp teeth so that it can eat flesh very easily. Do you know my pet dog’s name? I love my pet very much.

My code: 

s = ('my favourite animal is a dog. a dog has sharp teeth so that it can eat flesh very easily. do you know my pet dog’s name? i love my pet very much.')

output = ''
count = 0
fl = 0
for i in s:
    if count == 0:
        output += i.upper()
        count += 1
    elif i == ' ':
        output += i
    elif i == '.' or '!' or '?':
        output += i
        fl = 1
    elif fl == 1:
        output += i.upper()
        fl = 0
    else:
        output += i

print(output)

Upvotes: 1

Views: 129

Answers (1)

tsamridh86
tsamridh86

Reputation: 1496

Your third elif condition has a mistake,

You have done :

elif i == '.' or '!' or '?':

This means that '!' or '?' is being computed everytime, which always results to True and never reaches the next required elif fl == 1: condition which handles the upper() logic.

The correct elif condition would be :

elif i == '.' or i == '!' or i == '?':

(Edit) for a single 'i' in the string, you'll need to implement a lookahead, I have changed the code below.

The corrected code :

s = ('my favourite animal is a dog. a dog has sharp teeth so that it can eat flesh very easily. do you know my pet dog’s name? i love my pet i very much. i')

output = ''
count = 0
fl = 0
for i in range(len(s)):
    if count == 0:
        output += s[i].upper()
        count += 1
    elif s[i] == 'i':
        # handle end of string for the lookahead below
        if i == len(s)-1:
            output += s[i].upper()
        elif s[i+1] == ' ':
            output += s[i].upper()
    elif s[i] == ' ':
        output += s[i]
    elif s[i] == '.' or s[i] == '!' or s[i] == '?':
        output += s[i]
        fl = 1
    elif fl == 1:
        output += s[i].upper()
        fl = 0
    else:
        output += s[i]

print(output)

Upvotes: 1

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