CODEWITHSUNDEEP
python
Tyler P
Tyler P

Reputation: 147

Why is my python code printing "function" and a lot of numbers?

So I need to make a program that simulates the Powerball.

import random

def powerball():
  randInt = 0
  first_bin = [1]
  for i in range(1,70):
    first_bin.append(i)
#Create second bin - a list of integers from 1-26
  sec_bin = [1]
  for i in range(1,27):
    sec_bin.append(i)

#Mix up the bins - .shuffle()
  random.shuffle(first_bin)
  random.shuffle(sec_bin)

#Select 5 numbers from bin 1
#for loop
#.pop() to pull a ball
#.randInt to pick a position in the list
  for i in range(65):
    first_bin.pop(randInt)

#Sort our list of 5 numbers
  first_bin.sort
#Pick the Powerball from bin 2 - .choice() & append that to our list of 5 numbers
  ball = random.choice(sec_bin)
  power = first_bin.append(ball)
#return our list
  return power

#main program - call the function and print the result
print(powerball())

Whenever I try to run the program, it prints "function powerball at 0x7f10b46283a0". It only started doing this after the last couple of lines. What's going wrong? I checked and it seems like it would run fine.

Upvotes: 1

Views: 217

Answers (3)

Gilseung Ahn
Gilseung Ahn

Reputation: 2624

You can use

print(powerball())

instead of print(powerball).

Upvotes: 2

ppwater
ppwater

Reputation: 2277

reason

that's because you do append and you assign that to the variable.

how to fix it

try this code:

import random

def powerball():
  randInt = 0
  first_bin = [1]
  for i in range(1,70):
    first_bin.append(i)
#Create second bin - a list of integers from 1-26
  sec_bin = [1]
  for i in range(1,27):
    sec_bin.append(i)
  

#Mix up the bins - .shuffle()
  random.shuffle(first_bin)
  random.shuffle(sec_bin)

#Select 5 numbers from bin 1
#for loop
#.pop() to pull a ball
#.randInt to pick a position in the list
  for i in range(65):
    first_bin.pop(randInt)
#Sort our list of 5 numbers
  first_bin.sort() # fixed this sort -> sort()
#Pick the Powerball from bin 2 - .choice() & append that to our list of 5 numbers
  ball = random.choice(sec_bin)
  first_bin.append(ball) #added this
  power = first_bin #changed this
#return our list
  return power

#main program - call the function and print the result
print(powerball())

  1. I fixed power = first_bin.append(ball) this is wrong. append just appends something to the list and it returns nothing(none). so just call it first and set power to first_bin like this: power = first_bin

  2. use print(powerball()) instead of print(powerball)

  3. you have to use sort() instead of sort

Upvotes: 1

OneCricketeer
OneCricketeer

Reputation: 191831

The first issue is that you need to call the function, as mentioned.

The second is that append will modify the list, and always returns None, which you then return yourself. So, while the idea might be correct, you don't need another variable for it

For example

import random 
def powerball():
    first_bin = list(range(1, 70))
    random.shuffle(first_bin)
    result = sorted(first_bin[:5])
    ball = random.randint(1, 27) 
    result.append(ball)
    return result

print(powerball())

Upvotes: 1

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