Reputation: 25
its a long doubly linked list code. but the problem is when i overload the operator, i think the function is not getting called. I have tried to put a debugging line printing here, but that does never show up. so i wanted if two of my Doubly Linked List are equal , it should print true.
class Node
{
friend class Dlist;
private:
string s;
string language;
int noOfNode;
Node * Next;
Node * Prev;
};
class Dlist
{
private:
Node * Header;
Node * Trailer;
int n;
public:
Dlist();//default constructor
void AddFront(string e,string lang);
void Print();
void AddBack(string e,string lang);
void RemoveFront();
void RemoveBack();
int Empty(){ if (Header->Next==Trailer) return 1 ; else return 0;}
int CountLanguage(string lang);
int search (string r);
void RemoveWord(string tempW);
void changeIndex(Node* node,int newIndex);
void sortDLL();
void PrintRev();
void AddInOrder(string s, string language);
bool operator==(const Dlist &Q);
};
bool Dlist::operator ==(const Dlist &Q)
{
Node*tempL1=Header->Next;
Node *tempL2=Q.Header->Next;
int count=0;
cout<<"here"<<endl;
if(n==Q.n)
{
while(tempL1!=Trailer && tempL2!=Q.Trailer)
{
if(tempL1->s==tempL2->s && tempL1->language==tempL2->language
){
tempL1=tempL1->Next;
tempL2=tempL2->Next;
}
else return false;
}
return true;
}
else
return false;
}
int main()
{
Dlist *x = new Dlist;
Dlist *y = new Dlist;
Dlist *z = new Dlist;
inputX();
inputY();
cout<<endl<<"test if the first list and the second are equal?? :"<<endl;
cout<<(x==y)<<endl;
return 0;
}
Upvotes: 1
Views: 124
Reputation: 310940
For starters the operator should be declared with the qualifier const
bool operator==(const Dlist &Q) const;
In this statement
cout<<(x==y)<<endl;
the used expression is a comparison of two pointers x
and y
declared like
Dlist *x = new Dlist;
Dlist *y = new Dlist;
You need to compare the pointed objects like
cout<<( *x == *y )<<endl;
Pay attention to that there is a logical error in this code snippet
while(tempL1!=Trailer && tempL2!=Q.Trailer)
{
if(tempL1->s==tempL2->s && tempL1->language==tempL2->language
){
tempL1=tempL1->Next;
tempL2=tempL2->Next;
}
else return false;
}
return true;
Instead of the statement
return true;
you should write
return tempL1 == Trailer && tempL2 == Q.Trailer;
Upvotes: 2