CODEWITHSUNDEEP
php
Ęstiv Əstiv
Ęstiv Əstiv

Reputation: 190

Get content sent from the server using phps file_get_contents when the returned status is 400

I am using phps file_get_contents to connect with my API server. It works well when the server returns with 200 status (it return the content from the api server). The problem is when the api server returns with 400 status. If the api server returns with 400 status the function simply returns FALSE (not the content).
here is what I get from $http_response_header

[ "HTTP\/1.1 400 Bad Request", 
"Server: nginx\/1.16.1", 
"Date: Fri, 06 Nov 2020 05:39:09 GMT", 
"Content-Type: application\/json", 
"Content-Length: 117", 
"Connection: close", 
"Strict-Transport-Security: max-age=31536000; includeSubDomains; preload", 
"Access-Control-Allow-Origin: *", 
"Access-Control-Expose-Headers: Content-Length,Content-Type,Date,Server,Connection" ]

Now my question is how can I get the content sent fron the API server when the status is 400?

Upvotes: 2

Views: 39

Answers (2)

Álvaro González
Álvaro González

Reputation: 146460

You just need to enable the ignore_errors flag:

$context = stream_context_create([
    'http' => [
        'ignore_errors' => true,
    ],
]);
var_dump(file_get_contents('http://example.com/', false, $context));

Upvotes: 1

michal.jakubeczy
michal.jakubeczy

Reputation: 9469

You can rather use curl than file_get_contents as this one has better support for error handling:

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "{url}"); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
$output = curl_exec($ch);   

// handle any other code than 200
if(curl_getinfo($ch, CURLINFO_HTTP_CODE) !== 200) {
    // your handling code
    print_r($output);
}

curl_close($ch);

Upvotes: 1

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