CODEWITHSUNDEEP
.netmongodbf#mongodb-querymongodb.driver
alkasai
alkasai

Reputation: 4023

Projecting results from MongoDb Find in F#

I'm trying to query MongoDB using MongoDB.Driver and return a partial result using mongo projection.

I've figured out how to query without projection, but not a partial result. This is my function for finding results:

let Find<'a> collectionName (filterDefinition: FilterDefinition<'a>) =
    let collection = database.GetCollection<'a> collectionName
    collection.Find(filterDefinition).ToEnumerable() |> List.ofSeq

This is an example of how I call it:

let findByIdFilter id =
    Builders<MyModel>.Filter.Eq((fun s -> s.id), id)

let results = Find collectionName (findByIdFilter id)

Let's say my model is something like that:

type MyInnerModel = {
    zInner: bool
}

type MyModel = {
    id: ObjectId
    x: int
    y: double
    z: MyInnerModel
}

And these are my projections:

type MyModelProjection1 = {
    id: ObjectId
    y: double
}

type MyModelProjection1 = {
    id: ObjectId
    x: int
    z: MyInnerModel
}

How do I construct my queries for following scenarios:

Upvotes: 1

Views: 358

Answers (1)

nilekirk
nilekirk

Reputation: 2393

You can define your projections like so:

let projection1 =
    Builders<MyModel>.Projection.Expression(fun model ->
        { id = model.id; y = model.y })

let projection2 =
    Builders<MyModel>.Projection.Expression(fun model ->
        { id = model.id; x = model.x; z = model.z })

You can then use them in the following way:

    let one =
        collection
            .Find(fun m -> m.z.zInner = false)
            .Project(projection1).ToEnumerable() |> List.ofSeq

    let two =
        collection
            .Find(fun m -> m.x = 5)
            .Project(projection2).ToEnumerable() |> List.ofSeq

    let three =
        collection
            .Find(fun _ -> true)
            .Project(projection1).ToEnumerable() |> List.ofSeq

    let four =
        collection
            .Find(fun _ -> true)
            .Project(projection1).ToEnumerable() |> List.ofSeq

Upvotes: 2

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