CODEWITHSUNDEEP
linuxbashshell
Wrest
Wrest

Reputation: 125

Best way to compare multiples vars shell linux

I have an Ansible playbook which collects some informations and finally write into a file something like this :

VAR_A=14.12.103
VAR_B=14.12.103
VAR_C=14.12.103
VAR_D=14.12.103
VAR_E=14.12.103
VAR_F=14.12.103
VAR_G=14.12.103
VAR_H=14.12.103

Then, I use a shell script to compare theses values to be sure that every vars are each identical to the other.

What is the best way to compare theses vars ? Actually I do :

if [ "$VAR_A" = "$VAR_B" ] && [ "$VAR_B" = "$VAR_C" ] && [ "$VAR_C" = "$VAR_D" ] && [ "$VAR_D" = "$VAR_E" ] && [ "$VAR_E" = "$VAR_F" ] && [ "$VAR_F" = "$VAR_G" ] && [ "$VAR_G" = "$VAR_H" ]; then
  echo "OK"
  exit 0
else
  echo "KO"
  exit 2
fi

but i think that's not the best way..

Does somebody gots another solution ?

Thanks

Upvotes: 1

Views: 48

Answers (3)

KamilCuk
KamilCuk

Reputation: 141493

finally write into a file something like this :

I would:

[[ "$(sed 's/^VAR_[A-H]=//' file | uniq | wc -l)" -eq 1 ]]

That could be significantly slower, but more readable. An awk solution could be significantly faster.

I think in awk, you could, untested:

if awk -F'=' 'NR==1{l=$2} NR!=1{if ($2 != l) exit 1}' file; then

Upvotes: 1

anubhava
anubhava

Reputation: 785611

Using awk you may use:

if awk -F= 'NR == 1 {v = $2} $2 != v {exit 1}' file; then
   echo "OK"
   exit 0
else
   echo "KO"
   exit 2
fi

Upvotes: 1

Tom Sebty
Tom Sebty

Reputation: 302

Depends on what you define "best"? Are you looking for runtime? or clarity?

because you can use a loop to compare VAR_A to all others, and if any comparison is false return KO else OK.

I can't think of a way to make it faster in bash but will edit if anything comes to mind.

Upvotes: 1

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