CODEWITHSUNDEEP
javascriptarrays
TIMEX
TIMEX

Reputation: 271614

How do I get the last 5 elements, excluding the first element from an array?

In a JavaScript array, how do I get the last 5 elements, excluding the first element?

[1, 55, 77, 88] // ...would return [55, 77, 88]

adding additional examples:

[1, 55, 77, 88, 99, 22, 33, 44] // ...would return [88, 99, 22, 33, 44]

[1] // ...would return []

Upvotes: 332

Views: 311736

Answers (9)

Belldandu
Belldandu

Reputation: 2382

Here is one I haven't seen that's even shorter

arr.slice(1).slice(-5)

Run the code snippet below for proof of it doing what you want

const arr = [];
for (let i = 0; i < 8; i++) {
    arr.push(i);
    console.log(`Array ${i + 1}: ${arr} -> ${arr.slice(1).slice(-5)}`);
}

Another way to do it would be using lodash https://lodash.com/docs#rest - that is of course if you don't mind having to load a huge JavaScript minified file if you're trying to do it from your browser.

_.slice(_.rest(arr), -5)

Upvotes: 151

jsduniya
jsduniya

Reputation: 2474

Beginner solution:

var givme = function(n) {
    if(n.length == 1) {
        return [];
    }
    if(n.length > 5) {
        return n.slice(n.length-5, n.length);
    }
    if(n.length <= 5) {
       return n.slice(1, n.length);
    }
}

// console.log(givme([1, 55, 77, 88, 99, 22, 33, 44]));

Upvotes: 0

Nima Malaeri
Nima Malaeri

Reputation: 45

array.reverse()
     .slice(0,5)
     .reverse()  //if you wanna keep the order of last 5

const myOriginalArray = [...Array(10).keys()] //making an array of numbers

const instanceFromlastFiveItemsOfMyArray = [
    ...myOriginalArray.reverse().slice(0,5).reverse()
    ]

Upvotes: -1

Noel Schenk
Noel Schenk

Reputation: 726

You can do it in one line like this:

const y = [1,2,3,4,5,6,7,8,9,10];
const lastX = 5;
const res = y.filter((val, index, arr) => index > arr.length - lastX - 1);
    
console.log(res);

.filter((val, index, arr) => index > arr.length - 6)

Upvotes: 5

godblessstrawberry
godblessstrawberry

Reputation: 5048

ES6 way:

I use destructuring assignment for array to get first and remaining rest elements and then I'll take last five of the rest with slice method:

const cutOffFirstAndLastFive = (array) => {
  const [first, ...rest] = array;
  return rest.slice(-5);
}

cutOffFirstAndLastFive([1, 55, 77, 88]);

console.log(
  'Tests:',
  JSON.stringify(cutOffFirstAndLastFive([1, 55, 77, 88])),
  JSON.stringify(cutOffFirstAndLastFive([1, 55, 77, 88, 99, 22, 33, 44])),
  JSON.stringify(cutOffFirstAndLastFive([1]))
);

Upvotes: 7

Madhu Kumar
Madhu Kumar

Reputation: 405

var y = [1,2,3,4,5,6,7,8,9,10];

console.log(y.slice((y.length - 5), y.length))

you can do this!

Upvotes: 16

SLaks
SLaks

Reputation: 887255

You can call:

arr.slice(Math.max(arr.length - 5, 1))

If you don't want to exclude the first element, use

arr.slice(Math.max(arr.length - 5, 0))

Upvotes: 517

hhsadiq
hhsadiq

Reputation: 2933

If you are using lodash, its even simpler with takeRight.

_.takeRight(arr, 5);

Upvotes: 44

Arka
Arka

Reputation: 837

Try this:

var array = [1, 55, 77, 88, 76, 59];
var array_last_five;
array_last_five = array.slice(-5);
if (array.length < 6) {
     array_last_five.shift();
}

Upvotes: 14

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