CODEWITHSUNDEEP
pythondictionary
rpb
rpb

Reputation: 3299

How to check dict of a list is empty?

The idea is to check whether the following dict inside list inside dict is empty or not.

For example, the following dict

expected_false={"all_dict": [{"A": [1], "B": [], "C": [], "D": []}]}

should return empty to be false as the key 'A' has a value of 1.

whereas, the following should return empty to be true

expected_empty={"all_dict": [{"A": [], "B": [], "C": [], "D": []}]}

I tried the following code, but it give different than what I have in mind.

all(not d for d in expected_true['all_dict'][0])

Upvotes: 0

Views: 689

Answers (3)

Kerem Boyalı
Kerem Boyalı

Reputation: 11

Dictionaries are set of key-value pairs. Pseudo-code:

-Get value of 'all_dict' key inside of dictionary that named {expected_false}
-That 'all_dict' key has a value which is a list that contains only one item (which is an another dictionary)
-To address list item : ['all_dict'][0] (we reached first list item, which is a dictionary)
-Use dict.values() method to get all values of keys innermost dictionary
-And each of these values are also list by itself

expected_false['all_dict'][0].values()

Therefore the code above returns lists. And check everylist if there is any item in it. Then print result.

expected_false={"all_dict": [{"A": [1], "B": [], "C": [], "D": []}]}
for item in expected_false['all_dict'][0].values():
    if len(item)!=0:
        a=any(item)
        print(a)

Upvotes: 0

Alexander Lekontsev
Alexander Lekontsev

Reputation: 1012

any(len(item) for item in expected_true['all_dict'][0].values())

Upvotes: 2

Serial Lazer
Serial Lazer

Reputation: 1669

This should work:

print(not any(len(expected_false['all_dict'][x]) > 0 for x in expected_false['all_dict']))

Upvotes: 1

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