CODEWITHSUNDEEP
c#winformsreflectionproperties
Josef
Josef

Reputation: 2726

Set property of control using reflection

How to get/set property of Control (in this case Button)?

I tried on this way:

Type t = Type.GetType("System.Windows.Forms.Button");

PropertyInfo prop = t.GetType().GetProperty("Enabled");

if (null != prop && prop.CanWrite && prop.Name.Equals("button1"))
{
    prop.SetValue(t, "False", null);
}

but t is null. What is wrong here?

Upvotes: 0

Views: 577

Answers (1)

Dmitrii Bychenko
Dmitrii Bychenko

Reputation: 186803

First, you need the instance to set property at, it's button1:

 object instance = button1;

you may want to find it, e.g. let's scan all open forms of MyForm type, and look for Button with "button1" Name:

 using System.Linq;

 ...

 object instance = Application
   .OpenForms
   .OfType<MyForm>()
   .SelectMany(form => form.Controls.Find("button1", true))
   .OfType<Button>()
   .FirstOrDefault();

 ...

Then we are ready for Reflection:

 var prop = instance.GetType().GetProperty("Enabled");

 if (prop != null && prop.CanWrite && prop.PropertyType == typeof(bool))
   // we set false (bool, not string "False") value
   // for instance button1   
   prop.SetValue(instance, false, null);

Edit: If you want to obtain Type from string via Type.GetType(...) you want assembly qualified name:

 string name = typeof(Button).AssemblyQualifiedName;

And you'll get something like

System.Windows.Forms.Button, System.Windows.Forms, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089

Demo:

Type t = Type.GetType(
  @"System.Windows.Forms.Button, System.Windows.Forms, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089");

MessageBox.Show(t.Name);

Upvotes: 2

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