CODEWITHSUNDEEP
kotlindestructuring
zero
zero

Reputation: 2104

Expand a definite list into variables in Kotlin

Check this below code [this works fine]

val a = "1,2,3"

val split = a.split(",")
val x = split.get(0)
val y = split.get(1)
val z = split.get(2)

println(x) // 1
println(y) // 2
println(z) // 3

In Kotlin, is there a better way to get the value of a definite array into these variables, like

val a = "1,2,3"
val (i, j, k) = a.split(",") // ...{some magic code to put each item against variables i,j,k}

// This is how i want to use it
println(i) // 1
println(j) // 2
println(k) // 3

Upvotes: 4

Views: 1488

Answers (1)

Adam Millerchip
Adam Millerchip

Reputation: 23129

Did you actually try to run your code? It works just fine:

val a = "1,2,3"
val (i, j, k) = a.split(",")

println(i)
println(j)
println(k)

Output:

1
2
3

The reason it works is because of Kotlin's destructuring declarations. For lists, you can do this for up to 5 items because it has 5 component functions defined.

Upvotes: 10

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