CODEWITHSUNDEEP
python-3.xfile
23408924
23408924

Reputation: 135

Writing a function that works with a .txt file in Python 3

Hi I'm trying to write a function that has a path to a .txt file as input and outputs a list of all the words in the file in Python 3. I apologise in advance for my lack of understanding and poor formatting.

I managed to open the file but cannot really work with it as I'd hoped. I tried just making a long string of the entire file and then use str.split(" ") to get a list with all the words in the file. However, I just get <_io.TextIOWrapper which I'm not even sure what it means even after searching it up. Additionally, I tried to use str.strip() to get rid of the \n but then I got the Errormessage: "<_io.TextIOWrapper" object has no attribute "split" .

This is basically how I've tried opening the file so far and it did work. However, as previously mentioned I can't really make much more with it.

def do_sth(inp):
       with open(inp,"r") as file:

Is there an easy way to just open .txt files and for example count the words or sentences etc? (I have done this before but only with a few senteces or words that were not in a file)

edit: more context: This is what I have come up so far. If i do it any other way it will just take each character of the words. The text file I'm working with is a long text and hence I need to somehow first get rid of the punctuation, and then split the text at each space so I have a list of words. Not really sure how to work with this.

def task(inp):
    with open(inp,"r") as file:
        contents = file.read()
        words = contents.strip().split(" ")
        while "\n" in words:
            words.remove("\n")
        print(words)

Upvotes: 0

Views: 197

Answers (1)

AI Humanizer
AI Humanizer

Reputation: 432

f=open("file.txt", "r")
contents =f.read()
l = list(contents)

Now you got a list and can output that in your console

with print(l) source: reading and writing files in python

Upvotes: 1

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