CODEWITHSUNDEEP
pythonpython-3.xsumrangearithmetic-expressions
snotf
snotf

Reputation: 5

sum the range of two inputs[python 3]

This script will accept two whole number inputs . first input will always be (-) than the second. script will display sum of every other whole number inputs.

script will not print any other text to the console other than the result of the operation.

here's the code i've written - so far i'm able to accept input but it produces an infinite loop and doesn't sum.

thanks

if __name__ == "__main__":

# user inputs digits
start = int(input())
stop = int(input())

# sum the range of above
while start < stop:
    print(sum for i in range(start, stop, 2))

Upvotes: 0

Views: 789

Answers (3)

Enzo
Enzo

Reputation: 358

Your start is always smaller than stop so of course the loop always runs. If it was the other way around it would not even run once.

You have a for loop inside a while and that can be avoided as well:

# user inputs digits
start = int(input())
stop = int(input())

# sum the range of above
result = 0
for i in range(start, stop, 2):
    result += i

Or, even better,

result = sum(range(start, stop, 2))

Upvotes: 0

Aplet123
Aplet123

Reputation: 35560

If you want to sum the range, then you don't even need a loop, as the range basically acts as your loop:

# user inputs digits
start = int(input())
stop = int(input())

# sum the range of above
print(sum(range(start, stop, 2)))

Upvotes: 1

Cory Kramer
Cory Kramer

Reputation: 118021

In your problem start will always be less than stop, so the while loop never exits. Instead you can keep a variable that starts at start and increments by 2 until reaching stop.

# user inputs digits
start = int(input())
stop = int(input())

i = start
total = 0
while i < stop:
    total += i
    i += 2

For conciseness, this can simply be done with

total = sum(range(start, stop, 2))

Upvotes: 1

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