CODEWITHSUNDEEP
groovyoperatorsdsl
Dalibor Novak
Dalibor Novak

Reputation: 595

Is it possible to define a new operator in Groovy?

Is it possible to define a brand new operator in Groovy? I would like to express a trade where someone buys 200 items for the price of 10 like this:

def trade = 200 @ 10

Is this achievable?

Thanks

EDIT: I want to make it clearer that I am interested in defining an operator not adding a method. Cheers.

Upvotes: 6

Views: 1930

Answers (4)

Ben Creasy
Ben Creasy

Reputation: 4136

The official documentation has a section on Operator Overloading: https://groovy-lang.org/operators.html#Operator-Overloading

Here is a list from the docs: List of overloadable operators

Upvotes: 0

blackdrag
blackdrag

Reputation: 6508

We always wanted the ability to define an operator through the user in Groovy, but so far we haven't gotten around the problems that come along with that. So the current state is that Groovy does not support custom operators, only the ones that are already in use.

Upvotes: 6

han
han

Reputation: 26

Number.metaClass."@" {Integer x -> delegate * x} 

assert (2.'@' (2)) == 4

Upvotes: 0

Benjamin Muschko
Benjamin Muschko

Reputation: 33436

I am not quite sure how you can make this work for the @ sign but you could certainly add the operation like this which I actually find more expressive:

Number.metaClass.buyFor { Integer price ->
   delegate * price
}

def result = 200.buyFor(10)
println result

Upvotes: 2

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