CODEWITHSUNDEEP
javascriptcsssassgulp
Shibbir
Shibbir

Reputation: 2031

Combine all scss file to one css file using gulp

I have this gulpfile.js file.

Here, you can see that every .scss file is converted to the corresponding .css file but I want all .scss files will be converted to only one .css file which will be main.css. How can I do this?

var gulp = require('gulp');
var sass = require('gulp-sass');
var browserSync = require('browser-sync').create();

gulp.task('sass', function() {
    return gulp.src('app/scss/**/*.scss')
        .pipe(sass())
        .pipe(gulp.dest('app/css'))
        .pipe(browserSync.reload({
            stream: true
        }))
});

gulp.task('browserSync', function(done) {
    browserSync.init({
        server: {
            baseDir: 'app'
        },
    });
    done();
})

gulp.task('watch', gulp.series('browserSync', 'sass', function() {
    gulp.watch('app/scss/**/*.scss', gulp.series('sass'));
    gulp.watch("app/*.html", { events: 'all' }, function(cb) {
        browserSync.reload();
        cb();
    });
    gulp.watch('app/js/**/*.js', browserSync.reload);
}));

Upvotes: 1

Views: 2106

Answers (1)

dogyear
dogyear

Reputation: 308

have you tried putting in a concat before the piping in a destination? You'll need to import the concat function found here. The following should combine your files.

gulp.task('sass', function() {
    return gulp.src('app/scss/**/*.scss')
        .pipe(sass())
        // concat will combine all files declared in your "src"
        .pipe(concat('all.scss'))
        .pipe(gulp.dest('app/css'))
        .pipe(browserSync.reload({
            stream: true
        }))
    });

Upvotes: 3

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