CODEWITHSUNDEEP
python
PythonNoob
PythonNoob

Reputation: 65

How to make an argument give a value to a variable?

So I'm trying to make a saveload function using the shelve module. This is my code so far.

def sl(value=None,var,loadvar=None,s_l):
    global loadvar
    gamedata=shelve.open('game')
    if s_l=='s':
        gamedata[var]=value
        gamedata.close()
    if s_l=='l':
        loadvar=gamedata.get(var)
        gamedata.close()

So how do I get the function to give the value that it gets in this lineloadvar=gamedata.get(var) to the variable outside the function(the variable name is entered as loadvar) For example there is a variable named as variable1 and i have a value stored in the gamedata file under the name v. I then run the function as follows:

sl(v,variable1,l)

Now the value of variable1 should be equal to v. How do i do this?

Upvotes: 0

Views: 47

Answers (1)

Jasar Orion
Jasar Orion

Reputation: 332

There are two ways:

  1. returning to outsite the function using return loadvar and outside the function

    variable = sl(v,variable1,l)

  2. you can use globals()

    def sl(value=None,var,loadvar=None,s_l):
    global loadvar
    gamedata=shelve.open('game')
    if s_l=='s':
        gamedata[var]=value
        gamedata.close()
    if s_l=='l':
        globals()['loadvar']=gamedata.get(var)
        gamedata.close()

    then outside the function after its call you can use loadvars anywhere

Upvotes: 1

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