CODEWITHSUNDEEP
functionvariablesluavar
Former
Former

Reputation: 1

How can I change the original variable in lua

I want to change the original variable so the functions prints a different answer. I'm new to Lua, is this possible and how can I do it?

Here's my code:

io.write("Hello, what is your first player's name? ")
local name = io.read()
io.write('How old is Player 1? ')
local age = io.read()

function Recall()
    print("Your player's name: " ,name, "\nYour player's age: " ,age, "\n")
end

Recall()

io.write("What is your second player's name? ")
local name = io.read()
io.write('How old is Player 2? ')
local age = io.read()

Recall()

When I call the function the second time, it prints the name and age in the first input. Any suggestions?

Upvotes: 0

Views: 1009

Answers (2)

Doyousketch2
Doyousketch2

Reputation: 2147

right idea, just tweak it a little so you aren't using the same variables

io.write("Hello, what is your first player's name? ")
local name1 = io.read()
io.write('How old is Player 1? ')
local age1 = io.read()

function Recall( name, age )
    print("Your player's name: ", name, "\nYour player's age: ", age, "\n")
end

Recall( name1, age1 )

io.write("What is your second player's name? ")
local name2 = io.read()
io.write('How old is Player 2? ')
local age2 = io.read()

Recall( name2, age2 )

Upvotes: 1

Spar
Spar

Reputation: 1752

You created new locals and lose the access to locals with the same names.

To fix that remove local near second name and second age. (Near Player2).

As alternative solution you can make parameters to Recall function and pass arguments in it.

Upvotes: 2

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